C++ - Loops to Read Numbers and Check Odd or Even Number

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I have given here the code to read set of integers and display whether odd or even number

Source Code

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int main()

{

    std::cout << "Program to find ODD or Even Number\n";

    while(1)

    {

        int n = 0;

        std::cout << "\nEnter a number(-1 for Exit): ";

        std::cin >> n;

 

        if( n == -1)

            break;

 

        if((n % 2) == 0)

        {

            std::cout << n << " is a EVEN number.\n";

        }

        else

        {

            std::cout << n << " is a ODD number.\n";

        }

    }

    return 0;

 

}

Output

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Program to find ODD or Even Number

 

Enter a number(-1 for Exit): 1

1 is a ODD number.

 

Enter a number(-1 for Exit): 2

2 is a EVEN number.

 

Enter a number(-1 for Exit): 3

3 is a ODD number.

 

Enter a number(-1 for Exit): 4

4 is a EVEN number.

 

Enter a number(-1 for Exit): 5

5 is a ODD number.

 

Enter a number(-1 for Exit): 6

6 is a EVEN number.

 

Enter a number(-1 for Exit): 7

7 is a ODD number.

 

Enter a number(-1 for Exit): -1

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