C++ - Sorting Numbers

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C++ program for sorting numbers in ascending order is given on this page. This program will accept the number of elements as first input. Then it will use the for loop to input the elements list.

 

Two nested for loops are used for sorting in ascending order. If you need decending order program, then change the if condition from > to <.

 

Source Code

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#include <stdio.h>

#include <string>

 

// Program for ascending order of Numeric Values

 

int main()

{

    int max;

    std::cout << "\nProgram for Ascending order of Numeric Values";

    std::cout << "\n\nEnter the total number of elements: ";

    std::cin >> max;   

    std::cout << "\n

 

    int *numarray = new int[max];

 

    for(int i = 0; i < max; i++)

    {

        std::cout << "Enter [" << i + 1 << "] element: ";

        std::cin >> numarray[i];

    }

 

    for(int i = 0; i < max; i++)

    {

        for(int j = 0; j < max; j++)

        {

            if(numarray[i] < numarray[j])

            {

                int temp = numarray[i];

                numarray[i] = numarray[j];

                numarray[j] = temp;

            }

        }

    }

 

    std::cout << "\n\nThe numbers in ascending orders are given below:\n\n";

    for(int i = 0; i < max; i++)

    {

        std::cout << "Sorted [" << i + 1 << "] element: ";

        std::cout << numarray[i];

        std::cout << "\n";

    }

 

    delete [] numarray;

    return 0;

}

Output

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Program for Ascending order of Numeric Values

 

Enter the total number of elements: 5

 

Enter [1] element: 200

Enter [2] element: 400

Enter [3] element: 100

Enter [4] element: 500

Enter [5] element: 300

 

 

The numbers in ascending orders are given below:

 

Sorted [1] element: 100

Sorted [2] element: 200

Sorted [3] element: 300

Sorted [4] element: 400

Sorted [5] element: 500

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