Java - Intersection of Two Arrays
Here is the Java source code intersection of two arrays which means finding the common elements between two arrays. The good thing about this coding is it will allocate only the required memory. During the first iterator it will count how many number of unique elements and common elements are available in an array. Then use the count to allocate the memory and fill in the elements in its second iteration.
Source Code
import java.io.*;
class Intersection
{
static int[] Find_Common_Elements(int[] p1, int[] p2)
{
int count = 0;
for (int i = 0; i < p1.length; i++)
{
for (int j = 0; j < p2.length; j++)
{
if (p1[i] == p2[j])
{
count++;
break;
}
}
}
int[] result = new int[count];
count = 0;
for (int i = 0; i < p1.length; i++)
{
for (int j = 0; j < p2.length; j++)
{
if (p1[i] == p2[j])
{
result[count++] = p1[i];
break;
}
}
}
return result;
}
static int[] BubbleSort(int[] numarray)
{
int max = numarray.length;
for (int i = 1; i < max; i++)
{
for (int j = 0; j < max - i; j++)
{
if (numarray[j] > numarray[j + 1])
{
int temp = numarray[j];
numarray[j] = numarray[j + 1];
numarray[j + 1] = temp;
}
}
}
return numarray;
}
static int[] Find_Unique_Elements(int[] numarray)
{
BubbleSort(numarray);
int element = numarray[0];
int count = 1;
for (int i = 1; i < numarray.length; i++)
{
if (element == numarray[i])
continue;
else
{
element = numarray[i];
count++;
}
}
int[] result = new int[count];
count = 0;
element = numarray[0];
result[count++] = element;
for (int i = 1; i < numarray.length; i++)
{
if (element == numarray[i])
continue;
else
{
element = numarray[i];
result[count++] = element;
}
}
return result;
}
public static void main(String[] args)
{
int[] array1 = new int[] { 10, 20, 30, 40, 50, 60, 70, 80, 90, 100,
95, 85, 75, 65, 55, 45, 35, 25, 15, 05,
10, 15, 20, 25, 30, 35, 40, 45, 50, 55
};
int[] array2 = new int[] { 15, 25, 35, 45, 55,
12, 22, 32, 43, 52,
15, 25, 35, 45, 55
};
int [] p1 = Find_Unique_Elements(array1);
int [] p2 = Find_Unique_Elements(array2);
int [] result = Find_Common_Elements(array1, array2);
System.out.print("\n\nUnique Sorted Elements in Array1: ");
for(int i = 0; i < p1.length; i++)
System.out.print(p1[i] + " ");
System.out.print("\n\nUnique Sorted Elements in Array2: ");
for(int i = 0; i < p2.length; i++)
System.out.print(p2[i] + " ");
System.out.print("\n\nCommon (Intersection of) Elements in Array1 and Array2: ");
for(int i = 0; i < result.length; i++)
System.out.print(result[i] + " ");
System.out.println();
}
}
Output
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