Turbo C - Check whether given point lies on a Line Segment
Here is the Turbo C program to check whether given point lies on a line segment or not.
Find out the equation for the line seperately Y = MX + C
Where M = Slope of a Line and C = Intercept
To Find the slope of a line
slope = (y2 - y1) / (x2 - x1)
To Find the intercept of the line, intercept = y1 - (slope) * x1
Where c1 is the intercept of a line and m1 is the slope for the line.
NOTE: To check the given point lies on a line, Not a line segment, click here
Source Code
#include <stdio.h>
#include <math.h>
void main()
{
float slope, intercept;
float x1, y1, x2, y2;
float px, py;
float left, top, right, bottom; // Bounding Box For Line Segment
float dx, dy;
printf("Program to find whether the given point lies with in line segment:\n");
printf("Enter X1: ");
scanf("%f", &x1);
printf("Enter Y1: ");
scanf("%f", &y1);
printf("Enter X2: ");
scanf("%f", &x2);
printf("Enter Y2: ");
scanf("%f", &y2);
printf("Enter Point X: ");
scanf("%f", &px);
printf("Enter Point Y: ");
scanf("%f", &py);
dx = x2 - x1;
dy = y2 - y1;
slope = dy / dx;
// y = mx + c
// intercept c = y - mx
intercept = y1 - slope * x1; // which is same as y2 - slope * x2
// For Bounding Box
if(x1 < x2)
{
left = x1;
right = x2;
}
else
{
left = x2;
right = x1;
}
if(y1 < y2)
{
top = y1;
bottom = y2;
}
else
{
top = y1;
bottom = y2;
}
printf("Equation of the line: %.2f X %c %.2f\n", slope, ((intercept < 0) ? ' ' : '+'), intercept);
if( slope * px + intercept > (py - 0.01) &&
slope * px + intercept < (py + 0.01))
{
if( px >= left && px <= right &&
py >= top && py <= bottom )
{
printf("Given point lies in the line segment\n");
}
else
printf("Given point is outside the line segment\n");
}
else
printf("The point is outside the line segment\n");
}
Output
Program to find whether the given point lies with in line segment:
Enter X1: 1
Enter Y1: 2
Enter X2: 5
Enter Y2: 7
Enter Point X: 2.33
Enter Point Y: 3.67
Equation of the line: 1.25X +0.75
Given point lies in the line segment
Press any key to continue . . .
Program to find whether the given point lies with in line segment:
Enter X1: 1
Enter Y1: 2
Enter X2: 5
Enter Y2: 7
Enter Point X: 2.3
Enter Point Y: 3.6
Equation of the line: 1.25X +0.75
The point is outside the line segment
Press any key to continue . . .
|
|