Visual C++ - Reverse Number

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I have given here Visual C++ code to reverse a given number. It counts the digits and then it uses / and % operators and simple multiplication to reverse the number.

Source Code

#include <stdio.h>

#include <conio.h>

#include <math.h>

int CountNumberOfDigits_usingLog(int n)

{

   return (int) (log10((double)n) + 1);

}

int CountNumberOfDigits(int n)

{

   int numdgits = 0;

   do

   {

      n = n / 10;

      numdgits++;

   } while(n > 0);

   return numdgits;

}

void main()

{

    int i, n, number, numdigits, result;   

    printf("\nProgram to find the reverse of a number. Enter -1 to exit");

    while(1)

    {

        printf("\nEnter a number: ");

        scanf("%d", &number);

        if(number < 0)

            break;

        n = number;

        numdigits = CountNumberOfDigits(number);

        printf("\nNumber of digits in %d is: %d\n", number, numdigits);

        result = 0;

        for(i = 0; i < numdigits; i++)

        {

            result *= 10;

            result += n % 10;

            n = n / 10;

        }

        printf("The reverse of number %d is : %d\n", number, result);

    }

}

Output