Visual C++ - Check whether given point lies on a Line (Y = MX + C)

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Here is the Visual C++ program to check whether given point lies on a line or not.

 

We directly got the equation for the two lines Y = MX + C as input

 

Where M = Slope of a Line and C = Intercept

 

Solve the given point px and py with Y = MX + C.

 

NOTE: To check the given point lies on a line segment, click here

 

Source Code

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#include <iostream>

#include <math.h>

 

 

void main()

{

    float slope, intercept;

    float px, py;

 

    std::cout << "Program to find whether the given point lies on a line:\n";

    std::cout << "Enter Line1 - Slope: ";

    std::cin >> slope;

 

    std::cout << "Enter Line1 - Intercept: ";

    std::cin >> intercept;

 

    std::cout << "Enter Point X: ";

    std::cin >> px;

 

    std::cout << "Enter Point Y: ";

    std::cin >> py;

 

   

    std::cout << "Equation of the line: ";

    std::cout << slope << "X " << ((intercept < 0) ? ' ' : '+') << intercept << "\n";

 

    if( slope * px + intercept > (py - 0.01) &&

        slope * px + intercept < (py + 0.01))

    {

 

           std::cout << "Given point lies on the line\n";

    }

    else

        std::cout << "Given point is outside the line\n";

}

 

Output

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Program to find whether the given point lies on a line:

Enter Line1 - Slope: 1.25

Enter Line1 - Intercept: 0.75

Enter Point X: 2.33

Enter Point Y: 3.67

Equation of the line: 1.25X +0.75

Given point lies on the line

Press any key to continue . . .

 

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