Software & Finance





Visual C++ - Sum of 0 to N Numbers - n (n+1) / 2





Here is the Visual C++ program for the sum of 0 - N using the formula n (n+1) / 2.

 


Source Code


#include <iostream>

 

void main()

{

    int N, sum = 0;

    std::cout << "Program for sum of all numbers from 0 - N\n";

 

    std::cout << "Enter N: ";

    std::cin >> N;

   

    sum = N * (N+1) / 2;

 

    std::cout << "The sum of all numbers between 0 and " << N << " is: " << sum << "\n";

}

Output


 

Program for sum of all numbers from 0 - N

Enter N: 100

The sum of all numbers between 0 and 100 is: 5050